Photo AI

What is the Arrhenius definition of a base? Why is NH₃ considered to be a base according to Brønsted-Lowry theory? (6) Calculate the pH value of (i) a 0.50 M solution of hydrochloric acid, (ii) a 0.50 M solution of ethanoic acid - Leaving Cert Chemistry - Question b - 2018

Question icon

Question b

What-is-the-Arrhenius-definition-of-a-base?---Why-is-NH₃-considered-to-be-a-base-according-to-Brønsted-Lowry-theory?-(6)----Calculate-the-pH-value-of---(i)-a-0.50-M-solution-of-hydrochloric-acid,---(ii)-a-0.50-M-solution-of-ethanoic-acid-Leaving Cert Chemistry-Question b-2018.png

What is the Arrhenius definition of a base? Why is NH₃ considered to be a base according to Brønsted-Lowry theory? (6) Calculate the pH value of (i) a 0.50 M ... show full transcript

Worked Solution & Example Answer:What is the Arrhenius definition of a base? Why is NH₃ considered to be a base according to Brønsted-Lowry theory? (6) Calculate the pH value of (i) a 0.50 M solution of hydrochloric acid, (ii) a 0.50 M solution of ethanoic acid - Leaving Cert Chemistry - Question b - 2018

Step 1

What is the Arrhenius definition of a base?

96%

114 rated

Answer

The Arrhenius definition of a base is a substance that dissociates into OH⁻ (hydroxide ions) in water, producing an aqueous solution. This means that an Arrhenius base increases the concentration of hydroxide ions in an aqueous solution.

Step 2

Why is NH₃ considered to be a base according to Brønsted-Lowry theory?

99%

104 rated

Answer

According to Brønsted-Lowry theory, NH₃ (ammonia) is considered a base because it accepts a proton (H⁺). This characteristic defines it as a proton acceptor, which is the central aspect of Brønsted-Lowry acid-base theory.

Step 3

Calculate the pH value of (i) a 0.50 M solution of hydrochloric acid.

96%

101 rated

Answer

For hydrochloric acid (HCl), which is a strong acid, the pH can be calculated using the following equation:

pH=extlog[H+]pH = - ext{log}[H^+]

Since HCl dissociates completely in solution,

[H+]=0.50extM[H^+] = 0.50 ext{ M}
So,

= 0.30$$

Step 4

Calculate the pH value of (ii) a 0.50 M solution of ethanoic acid.

98%

120 rated

Answer

To calculate the pH of a 0.50 M solution of ethanoic acid (CH₃COOH), we use the acid dissociation constant (Kₐ):

K_a = rac{[H^+][A^-]}{[HA]}

Here, let the concentration of dissociated H⁺ be denoted as x:
Following the expression:

yielding the equation:

K_a = 1.8 imes 10^{-5} = rac{x*x}{0.50 - x}
For simplicity, we assume x is very small compared to 0.50, hence:

1.8 imes 10^{-5} = x^2 \ \ x = ext{sqrt}(1.8 imes 10^{-5} imes 0.50) \ ightarrow [H^+] = 0.012 ext{ M}$$ Thus, we can now calculate the pH: $$pH = - ext{log}(0.012) \ = 1.92$$

Step 5

Which of the two acid solutions was neutralised?

97%

117 rated

Answer

The acid solution that was neutralised can be identified from its pH curve. As sodium hydroxide (NaOH) is added, a steep rise in pH indicates that a strong acid was neutralised. If the pH rapidly increased before reaching a neutral point, it suggests that hydrochloric acid (HCl) has been neutralised.

Step 6

State two pieces of evidence from the pH curve in support of your answer.

97%

121 rated

Answer

  1. The rapid increase in pH at the equivalence point demonstrates the strong acidic nature of HCl being neutralised by NaOH.
  2. The pH remains relatively stable at 7 after neutralisation, indicating a complete reaction between the acid and base.

Step 7

What is the essential property of an indicator used to detect the end point in a titration between this acid and NaOH?

96%

114 rated

Answer

The essential property of an indicator used in this titration is that it must change color at a pH close to 7, which is the expected endpoint for strong acid and strong base titrations. Thus, the indicator should have a transition range (pH) that coincides with the steep vertical region of the pH curve.

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

Other Leaving Cert Chemistry topics to explore

;