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How many (i) electrons, (ii) neutrons, has the aluminium ion, \( ^{27}_{13}Al^{3+} \)? - Leaving Cert Chemistry - Question a - 2015

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How many (i) electrons, (ii) neutrons, has the aluminium ion, \( ^{27}_{13}Al^{3+} \)?

Worked Solution & Example Answer:How many (i) electrons, (ii) neutrons, has the aluminium ion, \( ^{27}_{13}Al^{3+} \)? - Leaving Cert Chemistry - Question a - 2015

Step 1

(i) electrons

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Answer

The aluminium ion ( ^{27}_{13}Al^{3+} ) has lost 3 electrons. The neutral aluminium atom has 13 electrons (equal to its atomic number). Therefore, the electron count for the ( Al^{3+} ) ion is:

13−3=1013 - 3 = 10

Thus, the aluminium ion has 10 electrons.

Step 2

(ii) neutrons

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Answer

The number of neutrons in an atom can be calculated by subtracting the atomic number (number of protons) from the mass number. For ( ^{27}_{13}Al^{3+} ), the mass number is 27 and the atomic number is 13:

27−13=1427 - 13 = 14

Thus, the aluminium ion has 14 neutrons.

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