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Write the electron configuration (s, p, etc.) of the oxygen (oxide) ion (O$^{2-}$). - Leaving Cert Chemistry - Question a - 2010

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Write the electron configuration (s, p, etc.) of the oxygen (oxide) ion (O$^{2-}$).

Worked Solution & Example Answer:Write the electron configuration (s, p, etc.) of the oxygen (oxide) ion (O$^{2-}$). - Leaving Cert Chemistry - Question a - 2010

Step 1

Write the electron configuration of O$^{2-}$

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Answer

The oxygen atom has 8 electrons in its neutral state, represented by the electron configuration:

1s22s22p41s^2 2s^2 2p^4

When it becomes an oxide ion (O2^{2-}), it gains 2 additional electrons, resulting in a total of 10 electrons. The new electron configuration is:

1s22s22p61s^2 2s^2 2p^6

Alternatively, this can also be expressed as:

[He]2s22p6[He] 2s^2 2p^6

where [He] stands for the electron configuration of helium, which is commonly used for shorthand notation.

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