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An equation for the combustion of methanol in oxygen is: 2CH3OH + 3O2 → 2CO2 + 4H2O ΔH = -1451 kJ Is this reaction exothermic or endothermic? Give a reason for your answer. - Leaving Cert Chemistry - Question 6a - 2018

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Question 6a

An-equation-for-the-combustion-of-methanol-in-oxygen-is:--2CH3OH-+-3O2-→-2CO2-+-4H2O--ΔH-=--1451-kJ--Is-this-reaction-exothermic-or-endothermic?-Give-a-reason-for-your-answer.-Leaving Cert Chemistry-Question 6a-2018.png

An equation for the combustion of methanol in oxygen is: 2CH3OH + 3O2 → 2CO2 + 4H2O ΔH = -1451 kJ Is this reaction exothermic or endothermic? Give a reason for yo... show full transcript

Worked Solution & Example Answer:An equation for the combustion of methanol in oxygen is: 2CH3OH + 3O2 → 2CO2 + 4H2O ΔH = -1451 kJ Is this reaction exothermic or endothermic? Give a reason for your answer. - Leaving Cert Chemistry - Question 6a - 2018

Step 1

Is this reaction exothermic or endothermic?

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Answer

The reaction is exothermic.

Step 2

Give a reason for your answer.

99%

104 rated

Answer

The enthalpy change (ΔH) is negative, indicating that heat is released during the reaction. Being a combustion reaction, methanol (CH3OH) is classified as a fuel, and combustion reactions typically release energy in the form of heat.

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