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A solid cylinder has a radius of 10 mm and a height of 45 mm - Leaving Cert Mathematics - Question Question 1 - 2013

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A solid cylinder has a radius of 10 mm and a height of 45 mm. (a) Draw a sketch of the net of the surface of the cylinder and write its dimensions on the sketch. (... show full transcript

Worked Solution & Example Answer:A solid cylinder has a radius of 10 mm and a height of 45 mm - Leaving Cert Mathematics - Question Question 1 - 2013

Step 1

Draw a sketch of the net of the surface of the cylinder and write its dimensions on the sketch.

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Answer

To draw the net of a cylinder, visualize it as consisting of two circles (the top and bottom bases) and a rectangle (the lateral surface). The circles will have a radius of 10 mm, which indicates their diameter is 20 mm.

The rectangle will have a height of 45 mm and a width equal to the circumference of the base, calculated as:

2πr=2π(10)=20π62.8 mm2 \pi r = 2 \pi (10) = 20\pi \approx 62.8 \text{ mm}

Thus, the net includes:

  • Two circles (each with a diameter of 20 mm, and a radius of 10 mm)
  • One rectangle (with height 45 mm and width 62.8 mm)

Step 2

Calculate the volume of the cylinder. Give your answer in terms of π.

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Answer

The volume of a cylinder is calculated using the formula:

V=πr2hV = \pi r^2 h

Substituting the known values:

  • Radius, r=10 mmr = 10 \text{ mm}
  • Height, h=45 mmh = 45 \text{ mm}

We get:

V=π(10)2(45)=π(100)(45)=4500π mm3V = \pi (10)^2 (45) = \pi (100)(45) = 4500\pi \text{ mm}^3

Step 3

Find the surface area of the sphere. Give your answer in terms of π.

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Answer

Since the sphere has the same volume as the cylinder, we use the volume of the sphere formula:

43πr3=4500π\frac{4}{3} \pi r^3 = 4500\pi

Equating the volumes:

43r3=4500    r3=4500×34=3375\frac{4}{3} r^3 = 4500\implies r^3 = 4500 \times \frac{3}{4} = 3375

Solving for rr:

r=33753=15 mmr = \sqrt[3]{3375} = 15 \text{ mm}

Now, using this radius, we can find the surface area (A) of the sphere:

A=4πr2=4π(15)2=4π(225)=900π mm2A = 4\pi r^2 = 4\pi (15)^2 = 4\pi (225) = 900\pi \text{ mm}^2

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