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The daily profit of an oil trader is given by the profit function $p = 96x - 0.03x^2$, where $p$ is the daily profit, in euro, and $x$ is the number of barrels of oil traded in a day - Leaving Cert Mathematics - Question 8 - 2015

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Question 8

The-daily-profit-of-an-oil-trader-is-given-by-the-profit-function--$p-=-96x---0.03x^2$,-where-$p$-is-the-daily-profit,-in-euro,-and-$x$-is-the-number-of-barrels-of-oil-traded-in-a-day-Leaving Cert Mathematics-Question 8-2015.png

The daily profit of an oil trader is given by the profit function $p = 96x - 0.03x^2$, where $p$ is the daily profit, in euro, and $x$ is the number of barrels of o... show full transcript

Worked Solution & Example Answer:The daily profit of an oil trader is given by the profit function $p = 96x - 0.03x^2$, where $p$ is the daily profit, in euro, and $x$ is the number of barrels of oil traded in a day - Leaving Cert Mathematics - Question 8 - 2015

Step 1

Complete the table below.

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Answer

To calculate the daily profit for different numbers of barrels traded, we will substitute the values of xx into the profit function p=96x0.03x2p = 96x - 0.03x^2.

  • For x=500x = 500: p=96(500)0.03(500)2=48000750=40,500p = 96(500) - 0.03(500)^2 = 48000 - 750 = 40,500€

  • For x=1000x = 1000: p=96(1000)0.03(1000)2=960003000=66,000p = 96(1000) - 0.03(1000)^2 = 96000 - 3000 = 66,000€

  • For x=1500x = 1500: p=96(1500)0.03(1500)2=1440006750=76,250p = 96(1500) - 0.03(1500)^2 = 144000 - 6750 = 76,250€

  • For x=2000x = 2000: p=96(2000)0.03(2000)2=19200012000=72,000p = 96(2000) - 0.03(2000)^2 = 192000 - 12000 = 72,000€

  • For x=2500x = 2500: p=96(2500)0.03(2500)2=24000018750=52,500p = 96(2500) - 0.03(2500)^2 = 240000 - 18750 = 52,500€

The completed table is:

Number of barrels (x)5001000150020002500
Daily profit (€) (p)4050066000762507200052500

Step 2

Draw the graph of the trader’s profit function on the axes below for $500 \, \leq \; x \; \leq \, 2500$, $x \in \mathbb{R}$.

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Answer

The graph of the profit function can be sketched using the calculated daily profits at the values of xx. Starting from the point (500, 40500) and connecting through the other points, it will show a parabolic curve peaking at around 1600 barrels traded.

Step 3

Use your graph to estimate: The daily profit when 1750 barrels are traded.

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Answer

Using the graph, we find that the daily profit when 1750 barrels are traded is approximately €76,125.

Step 4

Use your graph to estimate: The numbers of barrels traded when the daily profit is €600,000.

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Answer

From the graph, it appears that the numbers of barrels traded when the daily profit is €600,000 are approximately 850 or 2350 barrels.

Step 5

Use calculus to find the number of barrels of oil traded that will earn the maximum daily profit.

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Answer

To find the maximum profit, we first take the derivative of the profit function:

rac{dp}{dx} = 96 - 0.06x

Setting the derivative equal to zero to find critical points:

960.06x=096 - 0.06x = 0 x=1600 barrels \Rightarrow x = 1600 \text{ barrels}

Step 6

Find this maximum profit.

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Answer

Substituting x=1600x = 1600 back into the profit function:

p=96(1600)0.03(1600)2p = 96(1600) - 0.03(1600)^2 p=15360076800=76800p = 153600 - 76800 = 76800€

Thus, the maximum profit is €676,800.

Step 7

Calculate the value of k.

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Answer

To find the value of kk where the trader will not make a profit if he trades more than kk barrels of oil, we set the profit function equal to zero:

p=96x0.03x2=0p = 96x - 0.03x^2 = 0

Factoring gives: x(960.03x)=0x(96 - 0.03x) = 0 Thus, x=0x = 0 or x=3200x = 3200.

Hence, the value of kk is 3200 barrels.

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