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The events A and B are such that P(A) = 0.7, P(B) = 0.5 and P(A ∩ B) = 0.3 - Leaving Cert Mathematics - Question 1 - 2012

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The events A and B are such that P(A) = 0.7, P(B) = 0.5 and P(A ∩ B) = 0.3. (a) Find P(A ∪ B) (b) Find P(A | B) (c) State whether A and B are independent events, ... show full transcript

Worked Solution & Example Answer:The events A and B are such that P(A) = 0.7, P(B) = 0.5 and P(A ∩ B) = 0.3 - Leaving Cert Mathematics - Question 1 - 2012

Step 1

Find P(A ∪ B)

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Answer

To find the probability of the union of two events, we use the formula:

P(AB)=P(A)+P(B)P(AB)P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Substituting the given values:

P(AB)=0.7+0.50.3=0.9P(A ∪ B) = 0.7 + 0.5 - 0.3 = 0.9

Thus, the probability of A or B occurring is 0.9.

Step 2

Find P(A | B)

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Answer

To find the conditional probability of A given B, we use the formula:

P(AB)=P(AB)P(B)P(A | B) = \frac{P(A ∩ B)}{P(B)}

Substituting the known values:

P(AB)=0.30.5=0.6P(A | B) = \frac{0.3}{0.5} = 0.6

Hence, the conditional probability P(A | B) is 0.6.

Step 3

State whether A and B are independent events, and justify your answer.

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Answer

Two events A and B are considered independent if:

P(AB)=P(A)P(B)P(A ∩ B) = P(A) \cdot P(B)

Calculating the right side:

P(A)P(B)=0.70.5=0.35P(A) \cdot P(B) = 0.7 \cdot 0.5 = 0.35

Given that P(A ∩ B) = 0.3, we can see that:

0.30.350.3 \neq 0.35

Thus, A and B are not independent events, as their intersection probability does not equal the product of their individual probabilities.

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