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Question 7
The closed line segment [0, 1] is shown below. The first three steps in the construction of the Cantor Set are also shown: - Step 1 removes the open middle third of... show full transcript
Step 1
Step 2
Answer
To find the total length removed after n steps, we note that at each step, we remove segments of length which can be described as a geometric series. The length removed at the nth step is:
ext{Length removed} = rac{1}{3} imes rac{2}{3}^{(n-1)}.
Thus, the total length removed after n steps:
S_n = rac{1}{3} + rac{1}{9} + rac{1}{27} + rac{1}{81} + ullet ullet ullet + rac{1}{3 imes 3^{(n-1)}} = rac{1}{3} imes rac{1 - (rac{2}{3})^n}{1 - rac{2}{3}} = 1 - rac{2}{3^n}.
Step 3
Step 4
Step 5
Answer
The sum rac{1}{3} + rac{1}{27} + rac{1}{81} corresponds to segments that remain after removing the middle thirds in the construction of the Cantor Set. As these points are in the remaining segments, they are included in the Cantor Set.
Step 6
Answer
The limit of the series rac{1}{3} + rac{1}{27} + rac{1}{243} + ullet ullet ullet can be identified as:
S_{ ext{limit}} = rac{1}{3} imes rac{1}{1 - rac{1}{9}} = rac{1}{3} imes rac{9}{8} = rac{3}{8}. This point is in the Cantor Set.
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