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In a survey, the IQ scores of 1200 people were recorded - Leaving Cert Mathematics - Question 5 - 2017

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In a survey, the IQ scores of 1200 people were recorded. The mean score was 100 points and the standard deviation was 15 points. Assuming that IQ scores are normally... show full transcript

Worked Solution & Example Answer:In a survey, the IQ scores of 1200 people were recorded - Leaving Cert Mathematics - Question 5 - 2017

Step 1

Fill in the missing numbers on the horizontal axis.

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Answer

The horizontal axis represents the IQ scores based on a normal distribution. Since the mean is 100, the standard deviation is 15, we have the following key points:

  • Mean: 100
  • One standard deviation below the mean: 100 - 15 = 85
  • Two standard deviations below: 100 - 30 = 70
  • One standard deviation above the mean: 100 + 15 = 115
  • Two standard deviations above: 100 + 30 = 130
  • Three standard deviations below: 100 - 45 = 55
  • Three standard deviations above: 100 + 45 = 145

Thus, the missing numbers on the axis are: 55, 70, 85, 100, 115, 130, 145.

Step 2

A person is chosen at random from those surveyed. Use the Empirical Rule to find the probability that this person has an IQ score between 70 and 130 points.

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Answer

According to the Empirical Rule:

  • About 68% of the data falls within one standard deviation of the mean (between 85 and 115).
  • About 95% of the data falls within two standard deviations of the mean (between 70 and 130).

Thus, the probability that a randomly selected person has an IQ score between 70 and 130 is approximately 95%, or 0.95.

Step 3

Use the Empirical Rule to find the approximate number of people surveyed with an IQ score of between 85 and 115.

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Answer

From the previous calculations, we know that approximately 68% of the people fall within one standard deviation of the mean (between 85 and 115).

To find the number of people, we calculate:

0.68×12008160.68 \times 1200 \approx 816

Therefore, approximately 816 people surveyed had an IQ score between 85 and 115.

Step 4

Find the probability that the pupil chosen is a boy or a pupil who does not study chemistry.

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Answer

First, calculate the total number of pupils who study chemistry:

  • Boys who study chemistry: 6
  • Girls who study chemistry: 9 Total = 6 + 9 = 15

Next, calculate the number of pupils who do not study chemistry: Total pupils = 24 Pupils who do not study chemistry = 24 - 15 = 9.

To find the probability that the pupil chosen is either a boy or does not study chemistry, we use the formula:

P(BC)=P(B)+P(C)P(BC)P(B \cup C) = P(B) + P(C) - P(B \cap C)

Where:

  • P(B)P(B) = Probability of choosing a boy = (\frac{10}{24})
  • P(C)P(C) = Probability of choosing a pupil who does not study chemistry = (\frac{9}{24})
  • P(BC)P(B \cap C) = Probability of choosing a boy who does not study chemistry = 10 boys - 6 boys studying chemistry = 4 boys not studying chemistry = (\frac{4}{24})

Substituting these values into the formula gives us: P(BC)=1024+924424=1524P(B \cup C) = \frac{10}{24} + \frac{9}{24} - \frac{4}{24} = \frac{15}{24}

Thus, the probability is (\frac{15}{24}) or 62.5%.

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