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In the Cockcroft and Walton experiment, accelerated protons collided with lithium nuclei - Leaving Cert Physics - Question d - 2017

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In the Cockcroft and Walton experiment, accelerated protons collided with lithium nuclei. In each collision a proton collided with a lithium nucleus to produce two a... show full transcript

Worked Solution & Example Answer:In the Cockcroft and Walton experiment, accelerated protons collided with lithium nuclei - Leaving Cert Physics - Question d - 2017

Step 1

how the protons were produced

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Answer

Protons were produced by utilizing a reaction where deuterium is used as a target. Deuterium nuclei are bombarded by high-energy particles, leading to the release of protons through nuclear reactions.

Step 2

how the protons were accelerated

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Answer

The protons were accelerated using a Cockcroft-Walton generator, which utilizes a voltage multiplier circuit to generate high voltages. This high voltage creates an electric field that accelerates the protons towards the target.

Step 3

how the alpha-particles were detected

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Answer

Alpha-particles were detected using a zinc sulfide screen, which produces flashes of light when struck by alpha-particles. These flashes can then be observed and counted.

Step 4

Write the nuclear equation for this reaction

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Answer

The nuclear equation for the reaction can be represented as:

Li36+p112He24\text{Li}^6_3 + \text{p}^1_1 \rightarrow 2 \text{He}^4_2

(where 1 proton interacts with the lithium nucleus to produce 2 alpha particles).

Step 5

calculate the loss in mass and hence the energy released (in MeV)

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Answer

The mass of the lithium nucleus is approximately 1.165 \times 10^{-26} \text{ kg} and the loss in mass during the reaction is calculated as:

Loss in mass=3.09×1029 kg\text{Loss in mass} = 3.09 \times 10^{-29} \text{ kg}

Using the mass-energy equivalence E=mc2E = mc^2, the energy released can be calculated as:

E=3.09×1029 kg×(3×108 m/s)217.35 MeV.E = 3.09 \times 10^{-29} \text{ kg} \times (3 \times 10^8 \text{ m/s})^2 \approx 17.35 \text{ MeV}.

Step 6

Explain the historical significance of this experiment

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Answer

This experiment was historically significant as it verified the principle of energy-mass equivalence, E=mc2E = mc^2, by demonstrating nuclear transmutation through artificially accelerated particles. Additionally, it marked a pivotal advancement in the development of particle accelerators, contributing to further research in nuclear physics and earning a Nobel Prize for its discoveries.

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