Photo AI

An apple has a weight of 1 N and its volume is 121 cm³ - Leaving Cert Physics - Question (b) - 2019

Question icon

Question (b)

An-apple-has-a-weight-of-1-N-and-its-volume-is-121-cm³-Leaving Cert Physics-Question (b)-2019.png

An apple has a weight of 1 N and its volume is 121 cm³. Calculate the density of the apple. (acceleration due to gravity = 9.8 ms²)

Worked Solution & Example Answer:An apple has a weight of 1 N and its volume is 121 cm³ - Leaving Cert Physics - Question (b) - 2019

Step 1

Calculate the mass of the apple

96%

114 rated

Answer

To find the mass, we can use the formula relating weight (W), mass (m), and gravitational acceleration (g):

W=mgW = mg

From this, we can rearrange to find:

m=Wgm = \frac{W}{g}

Substituting in the given values:

m=1extN9.8extms20.102extkgm = \frac{1 ext{ N}}{9.8 ext{ ms}^2} \approx 0.102 ext{ kg}

Step 2

Calculate the density of the apple

99%

104 rated

Answer

Density (ρ\rho) is calculated by the formula:

ρ=mv\rho = \frac{m}{v}

where:

  • mm is the mass of the apple = 0.102 kg
  • vv is the volume of the apple = 121 cm³ (which needs to be converted to m³)

First, convert volume:

121extcm3=121×106extm3121 ext{ cm}^3 = 121 \times 10^{-6} ext{ m}^3

Now, calculate the density:

ρ=0.102extkg121×106extm3842.15extkgm3\rho = \frac{0.102 ext{ kg}}{121 \times 10^{-6} ext{ m}^3} \approx 842.15 ext{ kg m}^{-3}

Thus, the density of the apple is approximately:

843extkgm3843 ext{ kg m}^{-3}

Join the Leaving Cert students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

Other Leaving Cert Physics topics to explore

;