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The work function of tungsten is 4.50 eV - Leaving Cert Physics - Question (h) - 2014

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The work function of tungsten is 4.50 eV. Calculate the maximum kinetic energy of an electron ejected from a tungsten surface when electromagnetic radiation whose ph... show full transcript

Worked Solution & Example Answer:The work function of tungsten is 4.50 eV - Leaving Cert Physics - Question (h) - 2014

Step 1

Calculate the Energy of Incident Photon

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Answer

The energy of the incident photon can be expressed as the sum of the work function and the kinetic energy (KE) of the ejected electron. The formula used is:

Ephoton=Workfunction+KEelectronE_{photon} = Work \, function + KE_{electron}

Given:

  • Photon energy (EphotonE_{photon}) = 5.85 eV
  • Work function (extWorkfunction ext{Work function}) = 4.50 eV

Now, substituting the known values, we have:

5.85eV=4.50eV+KEelectron5.85 \, eV = 4.50 \, eV + KE_{electron}

Step 2

Rearrange to Find the Kinetic Energy

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Answer

Rearranging the equation to solve for the kinetic energy:

KEelectron=EphotonWorkfunctionKE_{electron} = E_{photon} - Work \, function Substituting the values:

KEelectron=5.85eV4.50eVKE_{electron} = 5.85 \, eV - 4.50 \, eV KEelectron=1.35eVKE_{electron} = 1.35 \, eV

Step 3

Convert Kinetic Energy to Joules (if required)

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To convert the kinetic energy from electronvolts to joules, we use the conversion factor:

1eV=1.6imes1019J1 \, eV = 1.6 imes 10^{-19} \, J

Thus, the kinetic energy in joules is:

KEelectron=1.35eV×1.6imes1019J/eV=2.16×1019JKE_{electron} = 1.35 \, eV \times 1.6 imes 10^{-19} \, J/eV = 2.16 \times 10^{-19} \, J

Step 4

Final Result

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Answer

The maximum kinetic energy of the electron ejected from the tungsten surface is therefore:

1.35 eV (or 2.16 x 10^-19 J) after conversion.

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